{"id":1037,"date":"2019-12-06T15:39:37","date_gmt":"2019-12-06T14:39:37","guid":{"rendered":"https:\/\/blogs.futura-sciences.com\/lehning\/?p=1037"},"modified":"2019-12-19T09:31:20","modified_gmt":"2019-12-19T08:31:20","slug":"les-rubans-de-pascal","status":"publish","type":"post","link":"https:\/\/blogs.futura-sciences.com\/lehning\/2019\/12\/06\/les-rubans-de-pascal\/","title":{"rendered":"Les rubans de Pascal"},"content":{"rendered":"<p>Blaise Pascal (1623 &#8211; 1662) a invent\u00e9 une m\u00e9thode ing\u00e9nieuse pour calculer le reste d&#8217;une division (sans l&#8217;effectuer) et donc de tester la divisibilit\u00e9 d&#8217;un nombre par un autre, que nous nommerons <i>n<\/i> dans la suite de cet article.<\/p>\n<h2>Une suite de restes<\/h2>\n<p>Pascal consid\u00e8re la suite des restes des puissances de 10 par <em>n<\/em> en commen\u00e7ant par 0, pour <em>n<\/em> = 7, cela donne :<\/p>\n<table>\n<tbody>\n<tr>\n<td width=\"77\">puissances<\/td>\n<td width=\"38\">0<\/td>\n<td width=\"38\">1<\/td>\n<td width=\"38\">2<\/td>\n<td width=\"38\">3<\/td>\n<td width=\"38\">4<\/td>\n<td width=\"38\">5<\/td>\n<td width=\"38\">6<\/td>\n<td width=\"38\">7<\/td>\n<td width=\"38\">8<\/td>\n<td width=\"38\">9<\/td>\n<td width=\"38\">10<\/td>\n<td width=\"38\">11<\/td>\n<td width=\"38\">12<\/td>\n<td width=\"38\">13<\/td>\n<\/tr>\n<tr>\n<td width=\"77\">restes<\/td>\n<td width=\"38\">1<\/td>\n<td width=\"38\">3<\/td>\n<td width=\"38\">2<\/td>\n<td width=\"38\">6<\/td>\n<td width=\"38\">4<\/td>\n<td width=\"38\">5<\/td>\n<td width=\"38\">1<\/td>\n<td width=\"38\">3<\/td>\n<td width=\"38\">2<\/td>\n<td width=\"38\">6<\/td>\n<td width=\"38\">4<\/td>\n<td width=\"38\">5<\/td>\n<td width=\"38\">1<\/td>\n<td width=\"38\">3<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<p>En effet, le reste de 1 est 1, celui de 10 est 3, celui de 100 est 2 (puisque 100 = 14 x 7 + 2), etc. La suite des restes est p\u00e9riodique. Ce r\u00e9sultat n&#8217;est pas li\u00e9 au nombre 7, il est g\u00e9n\u00e9ral. Cette suite est appel\u00e9e le ruban de Pascal associ\u00e9 au nombre 7.<\/p>\n<h2>Calcul du reste d&#8217;une division<\/h2>\n<p>A partir de ce ruban, pour calculer le reste de la division par 7 d&#8217;un nombre comme 348, on \u00e9crit les d\u00e9cimales de 348 dans l&#8217;ordre inverse en dessous du d\u00e9but du ruban :<\/p>\n<table>\n<tbody>\n<tr>\n<td width=\"83\">ruban<\/td>\n<td width=\"38\">1<\/td>\n<td width=\"47\">3<\/td>\n<td width=\"38\">2<\/td>\n<td width=\"38\"><\/td>\n<\/tr>\n<tr>\n<td width=\"83\">nombre<\/td>\n<td width=\"38\">8<\/td>\n<td width=\"47\">4<\/td>\n<td width=\"38\">3<\/td>\n<td width=\"38\"><\/td>\n<\/tr>\n<tr>\n<td width=\"83\">calculs<\/td>\n<td width=\"38\">8<\/td>\n<td width=\"47\">12=5<\/td>\n<td width=\"38\">6<\/td>\n<td width=\"38\">8+5+6=5<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<p>On effectue d\u2019abord les multiplications en colonnes de 1 par 8, 3 par 4 et 2 par 3. On retranche autant de fois 7 que possible, donc 12 est remplac\u00e9 par 5. On additionne alors les r\u00e9sultats obtenus et on retranche \u00e0 nouveau autant de fois 7 que possible, on trouve 5 qui est le reste de la division de 348 par 7.<\/p>\n<p><span style=\"font-size: 12.0pt;font-family: 'Arial',sans-serif\">Pourquoi\u00a0? Cela vient des r\u00e8gles de calcul sur les nombres modulo 7 (c&#8217;est-\u00e0-dire en ne gardant \u00e0 chaque \u00e9tape que le reste dans la division par 7). On part de 348\u00a0=\u00a03.10<sup>2<\/sup>\u00a0+\u00a04.10<sup>1<\/sup>\u00a0+\u00a08.10<sup>0<\/sup>. En rempla\u00e7ant, les puissances de 10 par leurs restes, on obtient\u00a0348\u00a0=\u00a03.2\u00a0+\u00a04.3\u00a0+\u00a08.1 mod 7. On effectue les multiplications et les additions en retranchant 7 autant de fois qu\u2019on peut et on a montr\u00e9 le bien fond\u00e9 de l\u2019algorithme utilis\u00e9 ainsi que sa g\u00e9n\u00e9ralit\u00e9. <\/span><\/p>\n<p><span style=\"font-size: 12.0pt;font-family: 'Arial',sans-serif\">On peut ainsi calculer tr\u00e8s rapidement le reste des divisions de tr\u00e8s grands nombres, comme celui de 56\u00a0218\u00a0491 par 7.<\/span><\/p>\n<table>\n<tbody>\n<tr>\n<td width=\"83\">ruban<\/td>\n<td width=\"47\">1<\/td>\n<td width=\"47\">3<\/td>\n<td width=\"47\">2<\/td>\n<td width=\"47\">6<\/td>\n<td width=\"47\">4<\/td>\n<td width=\"47\">5<\/td>\n<td width=\"47\">1<\/td>\n<td width=\"47\">3<\/td>\n<td width=\"47\"><\/td>\n<\/tr>\n<tr>\n<td width=\"83\">nombre<\/td>\n<td width=\"47\">1<\/td>\n<td width=\"47\">9<\/td>\n<td width=\"47\">4<\/td>\n<td width=\"47\">8<\/td>\n<td width=\"47\">1<\/td>\n<td width=\"47\">2<\/td>\n<td width=\"47\">6<\/td>\n<td width=\"47\">5<\/td>\n<td width=\"47\"><\/td>\n<\/tr>\n<tr>\n<td width=\"83\">calculs<\/td>\n<td width=\"47\">1<\/td>\n<td width=\"47\">27=6<\/td>\n<td width=\"47\">8=1<\/td>\n<td width=\"47\">48=6<\/td>\n<td width=\"47\">4<\/td>\n<td width=\"47\">10=3<\/td>\n<td width=\"47\">6<\/td>\n<td width=\"47\">15=1<\/td>\n<td width=\"47\">0<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><span style=\"font-size: 12.0pt;font-family: 'Arial',sans-serif\">On trouve rapidement que le reste est \u00e9gal \u00e0 0 donc que 56\u00a0218\u00a0491 est divisible par 7. Le test de divisibilit\u00e9 par 7 est donc de m\u00eame nature que le test de divisibilit\u00e9 par 9\u00a0: au lieu de faire la somme des chiffres, on en fait une combinaison lin\u00e9aire dont les coefficients sont ceux du ruban de Pascal. Il en est de m\u00eame pour tous les nombres.<\/span><\/p>\n<h2>Divers rubans<\/h2>\n<p><span style=\"font-size: 12.0pt;font-family: 'Arial',sans-serif\">Pour utiliser cette technique, il est bon de disposer d\u2019un certain nombre de rubans. Voici ceux des nombres premiers inf\u00e9rieurs \u00e0 20 o\u00f9 on s\u2019est arr\u00eat\u00e9 \u00e0 la partie p\u00e9riodique\u00a0:<\/span><\/p>\n<p>&nbsp;<\/p>\n<table>\n<tbody>\n<tr>\n<td width=\"31\">Nb<\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<\/tr>\n<tr>\n<td width=\"31\">2<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\">0<\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<\/tr>\n<tr>\n<td width=\"31\">3<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<\/tr>\n<tr>\n<td width=\"31\">5<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\">0<\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<\/tr>\n<tr>\n<td width=\"31\">7<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\">3<\/td>\n<td width=\"31\">2<\/td>\n<td width=\"31\">6<\/td>\n<td width=\"31\">4<\/td>\n<td width=\"31\">5<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<\/tr>\n<tr>\n<td width=\"31\">11<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\">10<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<\/tr>\n<tr>\n<td width=\"31\">13<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\">10<\/td>\n<td width=\"31\">9<\/td>\n<td width=\"31\">12<\/td>\n<td width=\"31\">3<\/td>\n<td width=\"31\">4<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<\/tr>\n<tr>\n<td width=\"31\">17<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\">10<\/td>\n<td width=\"31\">15<\/td>\n<td width=\"31\">14<\/td>\n<td width=\"31\">4<\/td>\n<td width=\"31\">6<\/td>\n<td width=\"31\">9<\/td>\n<td width=\"31\">5<\/td>\n<td width=\"31\">16<\/td>\n<td width=\"31\">7<\/td>\n<td width=\"31\">2<\/td>\n<td width=\"31\">3<\/td>\n<td width=\"31\">13<\/td>\n<td width=\"31\">11<\/td>\n<td width=\"31\">8<\/td>\n<td width=\"31\">12<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\"><\/td>\n<td width=\"31\"><\/td>\n<\/tr>\n<tr>\n<td width=\"31\">19<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\">10<\/td>\n<td width=\"31\">5<\/td>\n<td width=\"31\">12<\/td>\n<td width=\"31\">6<\/td>\n<td width=\"31\">3<\/td>\n<td width=\"31\">11<\/td>\n<td width=\"31\">15<\/td>\n<td width=\"31\">17<\/td>\n<td width=\"31\">18<\/td>\n<td width=\"31\">9<\/td>\n<td width=\"31\">14<\/td>\n<td width=\"31\">7<\/td>\n<td width=\"31\">13<\/td>\n<td width=\"31\">16<\/td>\n<td width=\"31\">8<\/td>\n<td width=\"31\">4<\/td>\n<td width=\"31\">2<\/td>\n<td width=\"31\">1<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<p><span style=\"font-size: 12.0pt;font-family: 'Arial',sans-serif\">On peut ainsi facilement d\u00e9terminer le reste d\u2019un nombre comme 521\u00a0365\u00a0941 dans la division par 19.<\/span><\/p>\n<table>\n<tbody>\n<tr>\n<td width=\"31\">1<\/td>\n<td width=\"55\">10<\/td>\n<td width=\"47\">5<\/td>\n<td width=\"47\">12<\/td>\n<td width=\"47\">6<\/td>\n<td width=\"47\">3<\/td>\n<td width=\"31\">11<\/td>\n<td width=\"31\">15<\/td>\n<td width=\"31\">17<\/td>\n<td width=\"31\"><\/td>\n<\/tr>\n<tr>\n<td width=\"31\">1<\/td>\n<td width=\"55\">4<\/td>\n<td width=\"47\">9<\/td>\n<td width=\"47\">5<\/td>\n<td width=\"47\">6<\/td>\n<td width=\"47\">3<\/td>\n<td width=\"31\">1<\/td>\n<td width=\"31\">2<\/td>\n<td width=\"31\">5<\/td>\n<td width=\"31\"><\/td>\n<\/tr>\n<tr>\n<td width=\"31\">1<\/td>\n<td width=\"55\">40=2<\/td>\n<td width=\"47\">45=7<\/td>\n<td width=\"47\">60=3<\/td>\n<td width=\"47\">36=17<\/td>\n<td width=\"47\">9<\/td>\n<td width=\"31\">11<\/td>\n<td width=\"31\">30=11<\/td>\n<td width=\"31\">85=9<\/td>\n<td width=\"31\">1+2+7+3+17+9+11+11+9=13<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><span style=\"font-size: 12.0pt;line-height: 200%;font-family: 'Arial',sans-serif\">Le reste de 521\u00a0365\u00a0941 dans la division par 19 est donc 13.<\/span><\/p>\n<p>&nbsp;<\/p>\n<h2><\/h2>\n<!-- AddThis Advanced Settings generic via filter on the_content --><!-- AddThis Share Buttons generic via filter on the_content -->","protected":false},"excerpt":{"rendered":"<p>Blaise Pascal (1623 &#8211; 1662) a invent\u00e9 une m\u00e9thode ing\u00e9nieuse pour calculer le reste d&#8217;une division (sans l&#8217;effectuer) et donc de tester la divisibilit\u00e9 d&#8217;un nombre par un autre, que nous nommerons n dans la suite de cet article. Une suite de restes Pascal consid\u00e8re la suite des restes des puissances de 10 par n &hellip; <a href=\"https:\/\/blogs.futura-sciences.com\/lehning\/2019\/12\/06\/les-rubans-de-pascal\/\" class=\"more-link\">Continuer la lecture de <span class=\"screen-reader-text\">Les rubans de Pascal<\/span>  <span class=\"meta-nav\">&rarr;<\/span><\/a><!-- AddThis Advanced Settings generic via filter on get_the_excerpt --><!-- AddThis Share Buttons generic via filter on get_the_excerpt --><\/p>\n","protected":false},"author":12,"featured_media":1039,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":"","_links_to":"","_links_to_target":""},"categories":[8,63,29],"tags":[373,390,389],"class_list":["post-1037","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-enigmes","category-histoire","category-maths-2","tag-arithmetique","tag-blaise-pascal","tag-critere-de-divisibilite"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v24.1 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Les rubans de Pascal, par Herv\u00e9 Lehning<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/blogs.futura-sciences.com\/lehning\/2019\/12\/06\/les-rubans-de-pascal\/\" \/>\n<meta property=\"og:locale\" content=\"fr_FR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Les rubans de Pascal, par Herv\u00e9 Lehning\" \/>\n<meta property=\"og:description\" content=\"Blaise Pascal (1623 &#8211; 1662) a invent\u00e9 une m\u00e9thode ing\u00e9nieuse pour calculer le reste d&#8217;une division (sans l&#8217;effectuer) et donc de tester la divisibilit\u00e9 d&#8217;un nombre par un autre, que nous nommerons n dans la suite de cet article. Une suite de restes Pascal consid\u00e8re la suite des restes des puissances de 10 par n &hellip; Continuer la lecture de Les rubans de Pascal &rarr;\" \/>\n<meta property=\"og:url\" content=\"https:\/\/blogs.futura-sciences.com\/lehning\/2019\/12\/06\/les-rubans-de-pascal\/\" \/>\n<meta property=\"og:site_name\" content=\"MATH&#039;MONDE, le blog d&#039;Herv\u00e9 LEHNING, agr\u00e9g\u00e9 de math\u00e9matiques\" \/>\n<meta property=\"article:published_time\" content=\"2019-12-06T14:39:37+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2019-12-19T08:31:20+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/blogs.futura-sciences.com\/lehning\/wp-content\/uploads\/sites\/13\/2019\/11\/pascal.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"620\" \/>\n\t<meta property=\"og:image:height\" content=\"508\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"\u00c9crit par\" \/>\n\t<meta name=\"twitter:data1\" content=\"\" \/>\n\t<meta name=\"twitter:label2\" content=\"Dur\u00e9e de lecture estim\u00e9e\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/blogs.futura-sciences.com\/lehning\/2019\/12\/06\/les-rubans-de-pascal\/\",\"url\":\"https:\/\/blogs.futura-sciences.com\/lehning\/2019\/12\/06\/les-rubans-de-pascal\/\",\"name\":\"Les rubans de Pascal, par Herv\u00e9 Lehning\",\"isPartOf\":{\"@id\":\"https:\/\/blogs.futura-sciences.com\/lehning\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/blogs.futura-sciences.com\/lehning\/2019\/12\/06\/les-rubans-de-pascal\/#primaryimage\"},\"image\":{\"@id\":\"https:\/\/blogs.futura-sciences.com\/lehning\/2019\/12\/06\/les-rubans-de-pascal\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/blogs.futura-sciences.com\/lehning\/wp-content\/uploads\/sites\/13\/2019\/11\/pascal.jpg\",\"datePublished\":\"2019-12-06T14:39:37+00:00\",\"dateModified\":\"2019-12-19T08:31:20+00:00\",\"author\":{\"@id\":\"\"},\"breadcrumb\":{\"@id\":\"https:\/\/blogs.futura-sciences.com\/lehning\/2019\/12\/06\/les-rubans-de-pascal\/#breadcrumb\"},\"inLanguage\":\"fr-FR\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/blogs.futura-sciences.com\/lehning\/2019\/12\/06\/les-rubans-de-pascal\/\"]}]},{\"@type\":\"ImageObject\",\"inLanguage\":\"fr-FR\",\"@id\":\"https:\/\/blogs.futura-sciences.com\/lehning\/2019\/12\/06\/les-rubans-de-pascal\/#primaryimage\",\"url\":\"https:\/\/blogs.futura-sciences.com\/lehning\/wp-content\/uploads\/sites\/13\/2019\/11\/pascal.jpg\",\"contentUrl\":\"https:\/\/blogs.futura-sciences.com\/lehning\/wp-content\/uploads\/sites\/13\/2019\/11\/pascal.jpg\",\"width\":620,\"height\":508},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/blogs.futura-sciences.com\/lehning\/2019\/12\/06\/les-rubans-de-pascal\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Accueil\",\"item\":\"https:\/\/blogs.futura-sciences.com\/lehning\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Les rubans de Pascal\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/blogs.futura-sciences.com\/lehning\/#website\",\"url\":\"https:\/\/blogs.futura-sciences.com\/lehning\/\",\"name\":\"MATH&#039;MONDE, le blog d&#039;Herv\u00e9 LEHNING, agr\u00e9g\u00e9 de math\u00e9matiques\",\"description\":\"Comment comprendre le monde moderne sans culture math\u00e9matique ? 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